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Please provide explanations to the following questions.


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WhatsApp Image 2019-12-12 at 4.02.22 PM.jpeg

WhatsApp Image 2019-12-12 at 4.02.37 PM.jpeg

4 . ( * , 4 ) = 4X 2 + 942 +36
first Consider 4 as Constant
4 ( X,4 ) = 8x
8 x1 = 8
Slope in x dissection.
( 10, 40 ) 2 0 01 4 RS)
Second Consider r as constant
Yy ( 1 , 4 ) = 942
Ly !
4 ( * , 4 )...

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subject to At4= 10
Maximize
* ( K,Y ) = MY
det g f ( x ,4 ) = * + 4 - 10
vy = avg
Vip = 2 ( 1, 1 )
So
d = y
- 1
a = *
- 2
X+4 = 10
by
X = 4
So
27 = (0
Y = 5
K = 5
So Maximum Value (515) at (x,4 )= 1

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