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Supposeg(x) is an even function, g(x)is continuous, and g(x)>0,g(0)=1, and 5 -5 g(x) dx = 1. DefineG(x)= x -5 g(t) dt and let G(-1) = 0.
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# Suppose g(x) is an even function, g(x) is continuous, and g(x)>0, g(0)=1, and ∫5-5x-5 (a) G(-5)(b) G(0)

g(x) dx = 1. Define G(x)=∫g(t) dt and let G(-1) = 0.4. Calculate the numerical values for the expressions given below, justifying your answers.

(c) G(1)

(d) d/dx G(x) evaluated at x=0

(e) d/dx G(x2) evaluated at x=0

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Subject: Calculus, Math

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