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# need to find the area for this question.

need to find the area for this question.  y=2x^2 and y= 16-4x

find the area for this question. y=2x2 and y= 16-4x
Here 2x2 = 16-4x
2x2 + 4x -16 =0 Now we intergrate y = 16-4x-2x2 with the lower limit as -4 and upper limit as
2 to find the are

answer = 40/3 The integral of y=2x^2 form 0 to 2 = 16/3 the integral of y=16-4x from 2 to 4 = 8 8 + 16/3... View the full answer

Here is a detailed explanation... View the full answer

:−
=2 = 16 − 4
2 = 16 − 4 =&gt; 2 + 4 − 16 = 0 =&gt; +2 −8=0 =&gt; = −4 , 2
=2 =8 = = 4− = 4 − 8 4 − − 2
3√2
32√2 = 32 − 8 −
= 24 −
= 2 3√2
32
3 40
.
3

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