Question

Analysis:  Redox Half reaction of titration #1. Fe2+, SO42-, NH4+, H2O, K+, MnO4-, H+

Finding concentration of KMnO4:

SOA:​MnO4- + 8H+ + 5e- → Mn2+ + 4H2O 

SRA:​(Fe2+ → Fe3+ + e-) x 5

 

Predicted Redox Reaction: MnO4- + 8 H+ + 5 Fe2+ → Mn2+ + 4 H2O + 5 Fe3+

 

 

​Therefore, the concentration of KMnO4(aq) is 0.00728 mol/L.

 

 

Finding concentration of H2O2:

 

Redox half reaction of titration #2

 

 

 

SOA: 

SRA:

 

Predicted Redox Reaction: 

 

Using Stoichiometry to find Concentration of H2O2.

 

 

Since is diluted by a factor of 40, the concentration is multiplied by 40.

 

 

 

Percent concentration of H2O2(aq) is 2.80% according to the table in the textbook.​

Analysis: Finding concentration of KMnO4: Redox Half reaction of titration #1. Fe2+,SO42-,NH4+,H2O, K+, MnO4-, H+ SOA:MnO4-+ 8H++ 5e- Mn2++ 4H2O...
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