Analysis: Redox Half reaction of titration #1. Fe2+, SO42-, NH4+, H2O, K+, MnO4-, H+
Finding concentration of KMnO4:
SOA:MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
SRA:(Fe2+ → Fe3+ + e-) x 5
Predicted Redox Reaction: MnO4- + 8 H+ + 5 Fe2+ → Mn2+ + 4 H2O + 5 Fe3+
Therefore, the concentration of KMnO4(aq) is 0.00728 mol/L.
Finding concentration of H2O2:
Redox half reaction of titration #2
Predicted Redox Reaction:
Using Stoichiometry to find Concentration of H2O2.
Since is diluted by a factor of 40, the concentration is multiplied by 40.
Percent concentration of H2O2(aq) is 2.80% according to the table in the textbook.
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