A batch of 1,000 kg of KCl is dissolved in sufficient water to make a saturated solution at 363 K, where the
solubility is 35 wt % KCl in water. The solution is cooled to 293 K, at which temperature its solubility is 25.4 wt %. a) What are the weight of water required for the solution and the weight of KCl crystals obtained? b) What is the weight of crystals obtained if 5% of the original water evaporates on cooling?
Answer: hare first app to calculate the amount of water present in the solution to make 35% KCL solution. Once you get the... View the full answer