A hydrocarbon feedstock is available at a rate of 106 mol/h, and consists of propane ( xA 0.2 ), n- butane ( xB 0.3 ), n-pentane ( xC 0.2 ) and n-hexane ( xD 0.3 ). The distillate contains all of the
propane in the feed to the unit and 80% of the pentane fed to the unit. The mole fraction of butane in the distillate is yB 0.4 . The bottom stream contains all of the hexane fed to the unit. Calculate the distillate and bottoms streams flow rate and composition in terms of mole fractions.
Flow rate of n- propane in feed stream 0.2 * 106mol/hr = 21.2mol/hr flow rate of n- butane in feed stream 0.3 *106 mol/hr =... View the full answer