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given the 3z^2 orbital which could and could not be the following set of quantum numbers?

given the 3z^2 orbital which could and could not be the following set of quantum numbers? explain.

a n=1 l=0 ml=0

b n=2 l=2 ml=1

c n=2 l=1 ml=0

d n=3 l=1 ml=1

e n=3 l=2 ml=0

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Solution: Option e... View the full answer

7 comments
  • n = 3 coefficient, l = (n -1) = 3 - 1 = 2.
    • Experienced_ran
    • Dec 01, 2016 at 12:38pm
  • can you explain a little more in depth?
    • paigeyamate
    • Dec 01, 2016 at 12:40pm
  • YES, n is stand for principle quantum number and is equal to shell number any electronic state is written as nz^2
    • Experienced_ran
    • Dec 01, 2016 at 12:45pm
  • here n = 3
    • Experienced_ran
    • Dec 01, 2016 at 12:45pm
  • l = (n - 1) = 3 - 1 = 2.
    • Experienced_ran
    • Dec 01, 2016 at 12:45pm
  • ml lies from - l to l here from -2 to 2.
    • Experienced_ran
    • Dec 01, 2016 at 12:46pm
  • Only option (e) satisfy all .
    • Experienced_ran
    • Dec 01, 2016 at 12:47pm

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