ammonia and hydrogen peroxide react to produce hydrazine (N2H4) and water according to: 2NH3(g) + H2O2(l) =>
2H2O(l) + N2H4(l) Use the reaction enthalpies for the rxns below to determine the overall deltaHrxn of the reaction shown in the previous equation:
N2(g) + 3H2(g) => 2NH3(g) deltaH= -91.8kJ
H2(g) + O2(g) => H2O2(l) deltaH= -187.8kJ
N2(g) + 2H2(g) => N2H4(l) deltaH= +50.6kJ
O2(g) + 2H2(g) => 2H2O(l) deltaH= -571.6kJ
My answer was -800.6 kJ and it was marked partially wrong, however, I honestly dont know how to approach this problem. I added all of the numbers together. Please show me explanations if possible thanks!