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A 10.0 g piece of pure aluminum is placed in 75.0 mL of 0.54 M hydrochloric acid at STP condition. They react as follows: 2Al + 6HCl 3H 2 ( g ) +...

12. A 10.0 g piece of pure aluminum is placed in 75.0 mL of 0.54 M hydrochloric acid at STP condition. They react as follows:

2Al + 6HCl → 3H2(g) + 2AlCl3

Calculate the following:


  1. Volume, in liters, of hydrogen gas. (5 points)


  1. Molarity of Al+3. (Assume 75.0 mL solution.) (5 points)


  1. Molarity of Cl-. (Assume 75.0 mL solution.) (5 points)

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