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A solution that is 0.10 M butane (C4H10) in hexane (C6H14), with a density of 0.66 g/cm3, can also be described as: [ Hint:

A solution that is 0.10 M butane (C4H10) in hexane (C6H14), with a density of 0.66 g/cm3, can also be described as:

[Hint: You may want to assume a 1 L or 1 kg sample of the solution to make the calculations easier, since the answer will not depend on how much solution you have.]


Select all that apply:


0.89 % butane by mass

0.15 m butane

0.013 mole fraction butane

0.00015 m butane

1.3 mole fraction butane

0.88 % butane by mass

Top Answer

0.10 M butane (C4H10) means 0.10 mole butane dissolved in 1000 ml solution. mass of solution = density * volume = 0.66 *... View the full answer

1 comment
  • correction: % butane = 5.8 * 100 / 660 = 0.8787 % = 0.88 %. so 0.88 % butane by mass.
    • tutor_007
    • Apr 01, 2018 at 11:09pm

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Other Answers

0.1M butane means there are 0.1moles of butane in 1L of solution density of the solution/mixture=0.66g/cm3 assumed volume of... View the full answer

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