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Calculate the heat when 10.0 g of aluminum reacts with excess oxygen at constant pressure to form aluminum oxide. 4 Al( s ) + 3 O 2 ( g ) 2 Al 2 O 3...

Calculate the heat when 10.0 g of aluminum reacts with excess oxygen at constant pressure to form aluminum oxide. 

4 Al(s) + 3 O 2 (g) → 2 Al 2 O 3 ( s) ΔHrxn = -3351 kJ

-837.8 kJ

-124.2 kJ

-310.5 kJ

-1675

-3351 kJ

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2 comments
  • why do you divide by 4?
    • mmnohsin
    • Apr 30, 2018 at 8:54pm
  • in this reaction, for 4 mole reaction of Al, heat produced = 3351 kJ. so for one mole Al reaction, heat produced = 3351 / 4 = 837.75 KJ. for 0.3706 mole Al reaction heat produced = 0.3706 * 837.75 = 310.5 KJ. as heat is produced. so -310.5 KJ
    • suvsam
    • Apr 30, 2018 at 8:59pm

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-310.5 kJ heat is produced... View the full answer

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