A flask contains a 0.3437 M solution of potassium hydroxide. The solution is titrated and reaches an equivalence point when 21.65 m L of a 0.6515M solution of HNO3 is added. Calculate the volume of the base solution:
HNO3 +KOH ----> KNO3 +HOH
A H2SO4 solution of unknown molarity is titrated with 1.209 M NaOH solution. The titration requries 42.27 mL of the NaOH solution to reach the equivalent point with 25.00mL of the H2SO4 solution. What is the molarity of the acid solution?
2NaOH +H2 SO4 ----> Na2 SO4 + 2HOH
Please show work.
Volume of the base = 41.04... View the full answer
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1) HNO 3 +KOH ----> KNO 3 +HOH MOLES of 21.65 m L of a 0.6515M solution of HNO 3 reacting... View the full answer