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Calculate the change in pH when 5.00 mL of 0.100 M HCl(aq) is added to 100.0 mL of a buffer solution that is 0.100 M in NH3(aq) and 0.100 M in NH4Cl(aq).


Calculate the change in pH when 5.00 mL of 0.100 M NaOH(aq) is added to the original buffer solution.

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V = 100 mL buffer... 0.1 M of each NH3, NH4+ so.. Buffer equation pOH = pKb +log(NH4+/N3) pKb = 4.75 for NH3 so... Initially... View the full answer

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