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# Calculate the amount of energy (in kJ) needed to change 15.5 grams of ice at 0.00 o C to water at 25.00 o C. The specific heat of water is 4.184 J/g....

Calculate the amount of energy (in kJ) needed to change 15.5 grams of ice at 0.00 oC to water at 25.00 oC. The specific heat of water is 4.184 J/g.oC and heat of fusion is 335 J/g.

Here is the explanation for... View the full answer

at 0 o C Q needed to melt ice= heat of fusion x mass Q1= 15.5 x 335=5192.5 J Q... View the full answer

1 comment
• In kJ: 6.81 kJ ............Hope you understood fully how to get the answer
• DrAlbert1
• May 03, 2018 at 9:29pm

7.14 kJ energy is needed to change... View the full answer

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