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The student determined the enthalpy of neutralization to be equal to -33.5 kJ/mol by mixing 100.0 mL 2.00 M HCl and 100.0 mL 2.00 M NaOH solutions....

6. The student determined the enthalpy of neutralization to be equal to -33.5 kJ/mol by mixing

100.0 mL 2.00 M HCl and 100.0 mL 2.00 M NaOH solutions. The temperature increased by 6.0oC.

The student suspected that the solutions prepared were wrong and titrated the NaOH solution. It

turned out the be that the concentration of NaOH was indeed 1.70 M. What was the concentration

of HCl solution used?

Top Answer

molar enthalpy of neutralization=Quantity of heat produced when base is added to acid/moles of the base present moles... View the full answer

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