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Given the pair of reactions shown below with their equilibrium constants, N2O(g) + 1/2 O2(g) = 2 NO(g) Kc=1.7 *10^-13 N2(g) + O2(g) = 2NO(g) Kc=4.

Given the pair of reactions shown below with their equilibrium constants,

N2O(g) + 1/2 O2(g) = 2 NO(g) Kc=1.7 *10^-13

N2(g) + O2(g) = 2NO(g) Kc=4.1*10^-31


Find the value of the equilibrium constant for the following equilibrium reaction:

N2(g) + 1/2O2(g) = N2O(g)


Answer is 2.4*10^-18

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N2O(g) + 1/2 O2(g) = 2 NO(g) Kc=1.7 *10^-13 N2(g) + O2(g) = 2NO(g) Kc=4.1*10^-31 To f ind the value of the equilibrium... View the full answer

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