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Examine the following reaction: 5FeCl 2 ( aq ) + KMnO 4 ( aq ) + 8HCl( aq ) 5FeCl 3 ( aq ) + MnCl 2 ( aq ) + KCl( aq ) + 4H 2 O( l ) a.

Examine the following reaction:

           5FeCl2(aq) + KMnO4(aq) + 8HCl(aq) → 5FeCl3(aq) + MnCl2(aq) + KCl(aq) + 4H2O(l)

           a. Indicate the oxidation numberor oxidation state of each of the element in both reactants and products.

       b. Which atom is oxidized? Which is reduced?

        c. which is the reducing agent? the oxidizing agent?

Top Answer

 a. oxidation number of Fe in FeCl2 = +2 and of Cl = -1 oxidation number of H in HCl = +1 and Cl = -1 oxidation number of... View the full answer

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Other Answers

Answer: a) Fe = +2 (In reactants) +3 (In propducts) Mn = +7 (In... View the full answer

(a) FeCl 2 --> Fe=+2 ; Cl= -1 HCl--> H=+1 ; Cl= -1 KMnO 4 --> Mn=+7 ; K=+1 ; O= -2... View the full answer

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