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The black oxide of iron, Fe3O4, occurs in nature as the mineral magnetite. This substance can also be made in the laboratory by the reaction between...

The black oxide of iron, Fe3O4, occurs in nature as the mineral magnetite. This substance can also be made in the laboratory by the reaction between red-hot iron and steam according the following: 3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g).

(a) When 36.0 g H2O are mixed with 67.0 g Fe, which is the limiting reagent? (b) What mass in grams of black iron oxide is produced? (c) What mass in grams of excess reactant remains when the reaction is completed?

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H2O is the limiting reactant. mass in grams of black iron... View the full answer

1 comment
  • sorry this is wrong calculation. correctio: 67.0 g Fe = 67.0 / 55.85 = 1.1996 mole. Fe is the limiting reactant. mass in grams of black iron oxide is produced = 1.1996 * 231.533 / 3 = 92.6 gm. mass in grams of excess reactant remains = 2.0 - (1.1996 * 4 / 3) = 0.400 mole = 0.400 * 18 = 7.20 gm
    • suvsam
    • May 06, 2018 at 6:11am

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Other Answers

a)reaction equation is as follows 3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g). moles of iron=67/55.845=1.1997moles moles of... View the full answer

(a) limiting reactant... View the full answer

2 comments
  • Point of correction at (c). moles of H2O consumed = moles of Fe used x 4/3 = 1.196 x 4/3 = 1.595 moles. Mass of H2O consumed = moles x molar mass = 1.595 x 18 = 28.71 g. Mass of H2O remaining after reaction is complete = 36 - 28.71 = 7.29 g.
    • ngareray
    • May 06, 2018 at 6:10am
  • Please accept my slight corrections
    • ngareray
    • May 06, 2018 at 6:11am

PART (a): Fe is the limiting reagent. PART (b):... View the full answer

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