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Given: BCl3(g) + 3 H2O(l)----to H3BO3(s) + 3 HCl(g) H= -26.9 kcal B2H6(g) + 6 H2O(g)---to 2 H3BO3(s) + 6 H2(g) H= -117.9 kcal 1/2 H2(g) + 1/2...

Given:

BCl3(g) + 3 H2O(l)----to H3BO3(s) + 3 HCl(g) H= -26.9 kcal

B2H6(g) + 6 H2O(g)---to 2 H3BO3(s) + 6 H2(g) H= -117.9 kcal

1/2 H2(g) + 1/2 Cl2(g)----to HCl(g) H= -22.1 kcal

Calculate the value of Hrxn for the reaction. Be careful with states!

B2H6(g) + 6 Cl2(g----to 2 BCl3(g) + 6 HCl(g)

Top Answer

B2H6(g) + 6... View the full answer

1 comment
  • can a liquid state water cancel the gas state water ? They have different H
    • heguanting200281beer
    • May 07, 2018 at 11:54am

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B2H6(g) + 6 Cl2(g----> 2... View the full answer

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