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the Ka of HF at 25 c is 6.8x10^-4, what is the pH of 0.15M aqueous solution of HF?

the Ka of HF at 25 c is 6.8x10^-4, what is the pH of 0.15M aqueous solution of HF? Please explain/show work. I know the answer is 2.00 but do not know how to get it.

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dissociation equation is as follows HF<------>H + +F - Let us apply the ICE table to calculate the... View the full answer

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