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The density of mercury (Hg, atomic mass 200.59 g/mol) is 13.53 g/cm 3 . The number of moles of Hg in 1.00x10 3 nm 3 of pure Hg is (a) 6.75x10 15 mol...


3.        The density of mercury (Hg, atomic mass 200.59 g/mol) is 13.53 g/cm3. The number of moles of Hg in 1.00x103 nm3 of pure Hg is


(a) 6.75x10−15 mol   (b) 67.5 mol   (c) 6.75x10−6 mol   (d) 6.75x10+3 mol  (e) 6.75x10−20 mol

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3 comments
  • Arithmetic correction please:= 1.00*10^3 nm^3*1*10^-21cm^3/nm^3 = 1*10^-18cm^3; Mass of mercury = 13.53 g/cm^3*1*10^-18cm^3 = 1.353*10^-17g; Moles of Hg = 1.353*10^-17g/200.59 g/mol; Moles of Hg = 6.75*10^-20 mol;
    • jackson1info
    • Oct 03, 2018 at 8:11pm
  • Correct option is: e) 6.75*10^-20 mol
    • jackson1info
    • Oct 03, 2018 at 8:12pm
  • Sorry for the arithmetic error I had made. Thank you for understanding
    • jackson1info
    • Oct 03, 2018 at 8:12pm

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option (e) 6.75x10... View the full answer

2 comments
  • how did u convert nm3 to cm3. for nano u have to multiply it by 10^-9 but when how do u convert m3 to cm3
    • JusticeUniverseCheetah38
    • Oct 03, 2018 at 8:03pm
  • 1 nm = 10^-7 cem. hence nm^3 = (10^-7 cem)^3
    • suvsam
    • Oct 03, 2018 at 8:07pm

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