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Alum is prepared by the following equation K + + Al 3+ + 2 SO 4 2- + 12 H 2 O 1 mole of alum 1. Calculate the theoretical yield of alum if you start...

Alum is prepared by the following equation

K+ + Al3+ + 2 SO42- + 12 H2O → 1 mole of alum

1. Calculate the theoretical yield of alum if you start with 1.0000 g of Al foil

2. Calculate the percent yield if you actually recovered 16.2105 g of alum

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