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Pb ( - ) - Pb` + Ze - ( Black lead ) E . = 0 .13 V Reduction @ the Cathode: The ved lead ( + ) is attracted to the cathodic electrode. Cathode Half -...

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Pb ( - ) - Pb` + Ze -
( Black lead )
E . = 0 .13 V
Reduction @ the Cathode:
The ved lead ( + ) is attracted to the cathodic electrode.
Cathode Half - reaction`
Plizt + Ze- - Pb#`
( + )
Free = - 0 .13\
Overall Cell Reaction\
( Red Lead )
P6- 4 P6 2#^_ Pb ^ _ Pb|
( + )
E call = - 0. 25 )
Finding Reduction Potential for non-copper electrode
Part I :
E ved :
only ( dry) in Q
Non Cu | Molenit's,
electrode metal ion
Cell Reaction
"RXN Quotient\ Value of\ E(V )\
\E ' ( V ) from
\volumeties
a. 390
\Cv ` PG - ( UPS ) + P6 2^
Wemust Eq .
0.5 M
Andhe\ Pb
0.5 M
0. 5
0. 5
0. 1 98
6. 50%
0.IM Anode
Su
0.1M
( v } + Su - CV(s) + 5^
0. 55
1'0
D. 116
lock Awade
My
1.0M | (^ ^My` Cu(S ) + My`
1. 914 V
1. 845 V
1.0M Anode | Z n
1. 0 M
(V # + AZA - ( V($1 + Z n\
1. 105
1. 112
alm Cathode * Ag. `
WU ` + Ay = CVCS ) + Ag `
al
0 . 340
in
1. 0 / 9 Anode \ Fe
1 : 0 M
GHT* Fe - CU(S ) + Fe `
0. 64 V
* Ag + te- - Ag
AG : DG' + RT IN Q_\
- - OZAV - 8.3/4 V x 298 K`
Signature
\Date
Witness / TA
96 , 485
Date
THE HAYDEN - MCNEIL STUDENT LAB NOTEBOOK
Note : Insert Divider Under Copy Sheet Before Writing

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VOLTAIC CELLS
EXPERIMENT 12
POST-LAB QUESTIONS:
Include a discussion of the following topics in your written report.
1. You measured E for one of the voltaic cells in Part I. Calculate the corresponding values
of AG and K for your cell. Since your reaction was spontaneous, what types of values
would you expect for Ec , AG, and K?
2. How do the class' values of SRP for each of the voltaic cells compare with the reported
values? Give reasons for why some of the values may be higher or lower than the
expected value.
3.
What are some other ways you might measure the concentration of an unknown copper
solution? Discuss the advantages and/or disadvantages of using the concentration cell.
SAMPLE

Top Answer

(1) For the electrochemical cell, Pb (s) |  Pb 2+  (aq) || Cu 2+  (aq) | Cu (s)  Anode half cell reaction- Pb (s)... View the full answer

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