write the chemical half reaction equation of Fe(CN)6 3- to Fe(CN)6 4- at equilibrium A: Fe(CN)6 3- + e- = Fe(CN)6 4- 2.
View the step-by-step solution to:

Question

1. write the chemical half reaction equation of Fe(CN)6 3- to Fe(CN)6 4- at equilibrium

A: Fe(CN)6 3- + e- =

Fe(CN)6 4-


2. for the cell described in q 1 equation to calculate Eworking in terms of concentrations of Fe(CN)6 3- and Fe(CN)6 4- using the Nernst equation assuming the temperature is 25C

A:

Eworking = Eworking +0.0592V/n *log [Fe(CN)6 3-]


3. mathematical expression to determine the half cell potential of silver-silver chloride reference electrode. at standard conditions, in a solution of 3.5M aqueous KCl, the standard reduction potential is 0.205V.

A: Ag | AgCl | KCl (3.5 M) || Fe3+, Fe2+ |pt

AgCl + e- =Ag + Cl- E=0.205V


4. How to combine the expressions from q2 and q3 to determine Ecell between a half cell containing ferri- and ferr-cyanide against a Ag/AgCl reference electrode. assume that the Reference is at standard conditions. (need help with this question)

Top Answer

View the full answer
IMG_20190923_150219.jpg

Sign up to view the full answer

Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

-

Educational Resources
  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question