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Can someone hep me with this questions please?  80
SYNT0432: Preparing Tetraaminecopper(II) Sulfate Monohydrate
3. We can prepare the yellow coordination compound potassium tris(oxalate)rhodate(III), Ka[Rh(C204)31,
by reacting potassium hexachlororhodate(III), K3[RhClo], and potassium oxalate, K2C204.
(1) Balance the chemical equation for this reaction, shown below.
3 Ka (RhClo](aq) +K2C204(aq) - K3[Rh(C204)=](s, yellow) BKCI(aq)
(2) If we combine 1 mol of Ka[RhClo] with 1 mol of K2C204, which compound is the limiting reagent?
KB ( RhCl6 )
9
(3) How many moles of Ka[Rh(C204)al could form from the reaction in (2)?
K
4. A student, using the reaction in 3.(1), combined 1.00 g of K3[KhClg] with 25.0 mL of 1.25M K2(204, and
isolated 0.96 y of KalRh(C204)3].
(1) Calculate the number of moles of K3[RhClo] the student used.
(2) Calculate the number of moles of K2C204 the student used.
1.25 moles
(3) Determine which reactant is the limiting reagent. Include all appropriate calculations.
(4) Calculate the theoretical yield of the synthesis, in grams, of Ka[Rh(C204)3].

View the full answer (2)
Molarity of K2 C20y = 1.25M = 1.25 modes
Volume ( in L) = 25 L= 0.025L
1000
Molarity
= no of moles
Volume ( in litres)
No. of moles
= 1. 25 moles L x (0.025L)
= 0.03125 mole
K 3 [ Rh Ce 6.] + 3...

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