Substance Normal boiling point HF 293 K F2 85 K The electron cloud of HF is smaller than that of F2 ,however, HF has a much higher boiling point than...
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Can someone answer all of these questions, following the instructions of the photos? Also, may someone explain how

they got their answers?


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Substance Normal boiling point HF 293 K
F2 85 K The electron cloud of HF is smaller than that of F2 ,however, HF has a much higher boiling point than F2 has. Which of the following
explains how the dispersion-force model of intermolecular attraction does not account for the unusually high boiling point of HF? F2 is soluble in water, whereas HF is insoluble in water. The F2 molecule has a greater mass than the HF molecule has. between H+ and F_ ions. (9 Liquid F2 has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions Liquid F2 has weak dispersion force attractions between its molecules, whereas liquid HF has both weak dispersion

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Flask A
Flask B
Flask C
Flask D
Four different liquid compounds in flasks at 20 C are represented above. The table below identifies the compounds. Flask C shows the most
particles in the vapor phase. Which of the following is not shown in the model but best helps to explain why flask C must contain pentane?
Name
Chemical Formula
Boiling Point ( C)
Pentane
CH 3 CH2 CH2 CH2 CH3
36
Hexane
CH 3 CH2 CH2 CH2 CH2 CH3
69
Heptane
CH 3 CH2 CH2 CH2 CH2 CH2 CH3
98
Octane
CH 3 CH 2 CH2 CH2 CH2 CH2 CH2 CH3
126
A
The random motion of the particles within the liquids

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Name Chemical Formula Boiling Point (°C) Pentane CH3 CH2 CH2 CH2 CH3
Hexane CH3 CH2 CH2 CH2 CH2 CH3 ® The random motion of the particles within the liquids The relative speeds of the vapor particles in each flask ® The strength of the intermolecular forces between the particles in the liquids l : l The structural formula of the molecules of the liquid and vapor in each flask

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Answer the following questions in terms of principles of chemical bonding and intermolecular forces. In each explanation where a comparison
is to be made, a complete answer must include a discussion of both substances. The following complete Lewis electron-dot diagrams may be
useful in answering parts of this question. H H H H H H H H
| | | | I | | I
H—C—C—C—C—C—H H—C—C—C—H
l | | | I | | I
H H H H H H H H
Pcmanc Propane
H
l : : :0:
H—C—jj—H (l! l:
,l‘ H/ \Q—H H/ \H
Methanol Methanoic (formic) acid Mcthanal (formaldehyde) a. At1 atm and 298 K, pentane is a liquid whereas propane is a gas. Explain.
b. At1 atm and 298 K, methanol is a liquid whereas propane is a gas. Explain. C. Indicate the hybridization of the carbon atom in each of the following:

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H
:0:
:0:
H-C-O-H
H
H
O-H
H-
H
Methanol
Methanoic (formic) acid
Methanal (formaldehyde)
a. At 1 atm and 298 K, pentane is a liquid whereas propane is a gas. Explain.
b. At 1 atm and 298 K, methanol is a liquid whereas propane is a gas. Explain.
c. Indicate the hybridization of the carbon atom in each of the following:
i. Methanol
ii. Methanoic (formic) acid
d. Draw the complete Lewis electron-dot diagram for a molecule of propanoic acid, HC3H502 .
e. Explain the following observations about the two carbon-oxygen bonds in the methanoate (formate) anion, HCO2 . You may draw a
Lewis electron-dot diagram (or diagrams) of the methanoate ion as part of your explanations.
i. The two carbon-oxygen bonds in the methanoate (formate) anion, HCO2 , have the same length.
ii. The length of the carbon-oxygen bonds in the methanoate (formate) anion, HCO2 , is intermediate between the length of the
carbon-oxygen bond in methanol and the length of the carbon-oxygen bond in methanal.

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