cantinn

II. Data Analysis

A. Identify a relationship between two of the properties you measured for brass by graphing. Try to

come up with an algebraic relationship that expresses the pattern you found. Graph paper is

provided at the back of this manual.

(13, 07 , 1:00 ) and ( 57.53, 6,00)

6.00-

(57. 53 , 6-00 )

m = 6100 - 1.00

( 41. 49 , 5.00)

57, 53- 13,07

=0 . 112

4.00-

b = (6100 ) - (0. 112 ) ( 57, 53 )

6 = - 0.44

3.00-

8( 26. 32 , 3.0 )

Algebraic Equation :

2(21.83, 2.20)

200

(18. 39,2.0)

y= 0.112x - 0.44

1.00

( 13. 07 , 1.00 )

10,06

20.00 30.00

40100

mass ( a )

50.00 60.00

B. On the same sheet of graph paper, graph the same variables for the aluminum. What are similarities

and differences in the two graphs? Offer an explanation for this.

9.00

( 24.90. 9. 70)

(24, 50 , 9.15 )

18.73, 2.50 ) and ( 24.50, 9.20)

(23.84, 8.90 )

(21.20, 7. 80)

m = 9. 20- 2.50

6.70

15.77

= 0.425

(19. 96, 7.201

24.50 - 8.73

6 = ( 2. 50 ) - (0. 425 ) (8,73 )

8 5.00

6 = - 1.21

Algebraic Equation:

3.00

P (8. 73, 2.50)

200

y = 0. 425 x - 1. 21

1. 00

10.00

70 , 00

30. 00

mass (92

40,00

50.00

60.00

C. Using a different combination of variables repeat the data analysis outlined in parts II.A and II.B.

BRASS ( length vs. mass )

Aluminum

(length us . mass )

( 7. 60, 24. 90 )

(5.00, 57.53 ) 1

125. ouL

(7. 30 , 24:50 ) .

50-00

20.00-

( 7,00, 23. 86 )

mass (o

40.00-

( 2.40 , 26.82 ) .

(3. 60 , 41.49

(5. 70 , 19.95 )

MO

30.00-

0.00

(2.80, 8.73)

20.00

( 1 .90 , 21.83 )

( 1.50 , 15. 34 )

5.00 -

(1.20 , 13.07

100

2,00

3.00 4.00 500 600 7.00 8.00

1.00

J.00

3:00

4.00

5.00

Length ( cm )

( 1.20 , 13. 07 ) and (3.60, 41. 49 )

Length (cm )

(2. 80, 8.73 ) and (7. 60, 24.90 )

Algebraic

m = 41.49- 13.07

Algebraic

Equation :

m = 24. 90- 8:73 -

28.42 - 11.84

7.60- 2.80

2 = 3.37

Equation:

3.60 - 1.20

2.4

y = 11. 84 x - 1, 13

b = (41. 49 )-(11,84) (3.40) = -1 134 x- 1. 13

6 = (24, 90 ) - (3. 37) (7,60 ) =-0.71

y = 3. 37 X- 0.71