A metal rod weighing 5.00 g and having a specific heat of 0.397 J / K / g in 22.7 ml of water is placed. The specific heat of the water is 4.
View the step-by-step solution to:


<pre class="ql-syntax">A metal rod weighing <span

class="hljs-number">5.00</span> g <span class="hljs-keyword">and</span> having a specific heat <span class="hljs-keyword">of</span> <span class="hljs-number">0.397</span> J / K / g <span class="hljs-keyword">in</span> <span class="hljs-number">22.7</span> ml <span class="hljs-keyword">of</span> water <span class="hljs-keyword">is</span> placed. The specific heat <span class="hljs-keyword">of</span> the water <span class="hljs-keyword">is</span> <span class="hljs-number">4.184</span> J / K / g <span class="hljs-keyword">and</span> the density <span class="hljs-keyword">of</span> the water <span class="hljs-keyword">is</span> approximated to <span class="hljs-number">1000</span> g / mL. The initial water temperature <span class="hljs-keyword">is</span> <span class="hljs-number">20.0</span>oC <span class="hljs-keyword">and</span> the initial temperature <span class="hljs-keyword">of</span> the metal rod <span class="hljs-keyword">is</span> <span class="hljs-number">80.9</span>oC. What <span class="hljs-keyword">is</span> the final temperature (<span class="hljs-keyword">in</span> oC) <span class="hljs-keyword">of</span> the water <span class="hljs-keyword">and</span> the metal rod? </pre>

Top Answer

View the full answer

(2 metal rod = - &amp;water
mass of water 2 22.7 milt wog /ml = 2270 0
5+0. 397 (TF - 80.90) = - (2270* 21-184 (TP -20)
1 + 9 85 ( (f - 80 . () = - 29497-68 ( TF - 20...

Sign up to view the full answer

Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.


Educational Resources
  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question