Consider the following reaction:
2 CCl4(g) +
H2(g) C2H2(g) + 4 Cl2(g)
The enthalpy change at 298 K for this reaction is Horxn = 440.1 kJ/mol. Under the same conditions the entropy change for the reaction is Sorxn = 343.26 J/mol-K. Calculate the value of Keq for this reaction at 2480 K. Assume that Horxn and Sorxn are the same at 2480 K as they are at 298 K. Use R = 8.314 J/K for the value of the gas constant.
a) At this temperature Keq = 7.67e-08.
b) At this temperature Keq = 1.02e+00.
c) At this temperature Keq = 8.35e+17.
d) At this temperature Keq = 2.18e-09.
e) At this temperature Keq = 4.58e+08.
The right answer was e...Please can you explain how we got e?