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Consider the following reaction:

2 CCl4(g) +

H2(g)  C2H2(g) + 4 Cl2(g)

The enthalpy change at 298 K for this reaction is Horxn = 440.1 kJ/mol. Under the same conditions the entropy change for the reaction is Sorxn = 343.26 J/mol-K. Calculate the value of Keq for this reaction at 2480 K. Assume that Horxn and Sorxn are the same at 2480 K as they are at 298 K. Use R = 8.314 J/K for the value of the gas constant.

a) At this temperature Keq = 7.67e-08.

b) At this temperature Keq = 1.02e+00.

c) At this temperature Keq = 8.35e+17.

d) At this temperature Keq = 2.18e-09.

 e) At this temperature Keq = 4.58e+08.

The right answer was e...Please can you explain how we got e?

Top Answer

e) At this... View the full answer

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