The first part of the question is Convert the mass of NaHCO3 used and mass of NaCl obtained to moles. I got NaHCO3 = 84.01 g/mol and NaCl = 58.44...
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Question

The first part of the question is

Convert the mass of NaHCO3 used and mass of NaCl obtained to moles. I got

NaHCO3 = 84.01 g/mol and NaCl = 58.44 g/mol I divided both and got 1.437


Determine the theoretical yield NaCl in the NaHCO3 reaction.


Determine the percent yield for the NaHCO3 reaction.


Divide your answer from question 1 by the lower mole value to determine the simplest mole-to-mole ratio between NaHCO3 and NaCl. Calculate answer and then round to the nearest whole number.


Can I see a step by step? I am a visual learner

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The percentage yield of... View the full answer

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