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This question was created from Lab 5 Identification of a Compound


2. If 0.485 g of K2COs were reacted according to the following equation, what would be the
expected mass of the KCl product?
K2CO3(s) + HCl(aq) - 2 KCI(s) + H20(g) + CO2(9)

Top Answer

Mass of KCl= 0.523246 grams... View the full answer


1 2 Coz + 2 H CL .- > 2 KCL + 120 + co,
0 . 485g OF K, Coz Briefed
molar mass OF K2 coz = 138: 205 g / ml
Moles Of KaCoz that practed is equal to
I moll OF K2 CO3 = 138.205 gRms
What about D....

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