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61.7 grams of a solid with a specific heat capacity of 0.446 J g-1 °C-1 at an initial

temperature of 24.35 °C absorbed 329 J of heat. The final temperature of the solid was ___°C

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The final... View the full answer

P_20191211_050517.jpg

m z 61. 79
C = 0 . 46 6 7 9- 1 . C - 1
Initial temperature I = 24. 35 0
Final temperature
T . = ?
Heat absorbed q = 329 J
Heat absorbed q = mc ( T 2 - T. )
9 - T 2 - It
mc
2 + T = Iz
mc
329 7
* 24....

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