Please help to answer the following question:
Actual yield (CaCO3):
Moles of Ca present in original solution, based on actual yield:
Mass of CaCl2 present in original solution, based on actual yield
Please show step by step solution so that i could follow along. Thank you.
Actual yield CaCO 3 = 2.2 g(amount of CaCO 3 obtained in the given reaction) Theoretical yield CaCO 3 =1.8 g CaCO 3... View the full answer