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Please help to answer the following question:


Theoretical yield

(CaCO3): 

 

Actual yield (CaCO3): 

 

Percent yield: 

 

Moles of Ca present in original solution, based on actual yield:

 

Mass of CaCl2 present in original solution, based on actual yield


Please show step by step solution so that i could follow along. Thank you.


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Top Answer

Actual yield CaCO 3 = 2.2 g(amount of CaCO 3 obtained in the given reaction) Theoretical yield CaCO 3 =1.8 g CaCO 3... View the full answer

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