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When 1.045 g Na2O is added to 50.0 mL of water at 25.0 ∘C in a calorimeter, the temperature of the water

increases to 54.4 ∘C.

Assuming that the specific heat of the solution is 4.18J/(g⋅∘C) and that the calorimeter itself absorbs a negligible amount of heat, calculate ΔH

ΔH in kilojoules/mol for the reaction


Express the change in enthalpy in kilojoules per mole.

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The way to approach this... View the full answer

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Thus 0.017 mol gives out -6144.6 J =... View the full answer

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