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# LIQUID EXTRACTION PROBLEM 12.5-1 Plot equation data from A.3-24 F=200 kg original mixture xAM = 20/200 = 0.10 wt fraction of acetic acid xBM =...

how to draw a tie line in a triangular diagram for extraction process?
LIQUID EXTRACTION PROBLEM 12.5-1 Plot equation data from A.3-24 F=200 kg original mixture x AM = 20/200 = 0.10 wt fraction of acetic acid x BM = 130/200 = 0.65 wt fraction of water x CM = 50/250 = 0.25 wt fraction of ether Plot point m. A tie line through m gives L 1 and V 1 . From an enlarged graph we get as follows L 1 raffinate layer X A1 = 0.118 X C1 = 0.021 V 1 extract layer ; y A1 = 0.043 y C1 = 0.948 Material balance for L 1 and V 1 Eq. (12.5-12) m= 200= L 1 + V 1 or L 1 = 200-V 1 Eq. (12.5-13) m x AM = 200(0.10) = L 1 X A1 + V 1 Y A1 = L 1 (0.118)+ V 1 (0.043) Solving V 1 = 48.0 L 1 = 152.0 kg Graphical method for L 1 V 1 EQ. 12.5 -11 L/m = Vm/Lv = 69.8/92.6 = L/200 L 1 = 150.8 (Close Check)
PROBLEM 12.5 -2 EQ. (12.5-12)
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