What volume of O2 is required to react with excess CS2 to produce 4.0L of CO2 Assume all gases at STP.

Not sure what I am doing wrong, but the answer I am getting is not one of the answers.

4L/X mole=22.4 L/1 mole ===>.1786 mols

Balanced equation:

O2 + CS2 --> CO2 + S2

.1786 mols of each since it is a 1-1-1-1 equation.

Therefore, I am getting .1786 mols of O2 to make .1786 (4 L) CO2. .1786 mols O2 is 4 liters.

My answer options are

A) 12 L

B) 22.4 L

C) 1/3 x 22.4 L

D) 2 x 22.4 L

E) 3 x 22.4 L

What am I doing wrong here?

Not sure what I am doing wrong, but the answer I am getting is not one of the answers.

4L/X mole=22.4 L/1 mole ===>.1786 mols

Balanced equation:

O2 + CS2 --> CO2 + S2

.1786 mols of each since it is a 1-1-1-1 equation.

Therefore, I am getting .1786 mols of O2 to make .1786 (4 L) CO2. .1786 mols O2 is 4 liters.

My answer options are

A) 12 L

B) 22.4 L

C) 1/3 x 22.4 L

D) 2 x 22.4 L

E) 3 x 22.4 L

What am I doing wrong here?