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The oxidation of FADH2 to form FAD: FADH2 (right arrow) FAD + 2H+ + 2e- this has a potential E (prime)=0.219 under biological conditions (pH=7.00) @...

The oxidation of FADH2 to form FAD:
FADH2 (right arrow) FAD + 2H+  + 2e-
this has a potential E (prime)=0.219 under biological conditions (pH=7.00) @ 298 K. What is the potential for this process under standard conditions?
Please- I need a detailed explanation- not just numbers- I am using this as a study guide for my final- Thanks!!

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