2Al(s) +3 Cl2(g) ---> 2 AlCl3(s)
A. 2.5gAl , 2.5g Cl2
B. 7.7 g Al , 25.2 g Cl2
C. 0.240 g Al , 1.10 g Cl2
This question was asked on May 01, 2010.
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