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During the electrolysis of an aqueous solution of CuSO4 with inert electrodes (A) the anode loses mass and the cathode gains mass.

During the electrolysis of an aqueous solution of CuSO4 with inert electrodes
(A) the anode loses mass and the cathode gains mass.
(B) the mass of the anode remains the same but the cathode gains mass.
(C) the mass of the anode decreases but the mass of the cathode remains constant.
(D) the anode and the cathode neither gain nor lose mass.
(E) both electrodes gain in mass.
I was thinking in Electrolysis of CuSO4(aq)
Anode: 2H2O O2(g) + 4H+1 + 4e-1 -1.23V
Cathode: 2 Cu+2+ 4e-1 2Cu + 0.34V
Overall: 2H2O + 2 Cu+2 O2(g) + 4H+1 + 2Cu Eー = -1.02V
that it would be D because it doesnt really change in either

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