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A solution contains 1.35 g of Ca(OH)2 in 875 mL of solution. Find the normality of the solution.

A solution contains 1.35 g of Ca(OH)2 in 875 mL of solution. Find the normality of the solution.

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Molecular mass = 74
Equivalent mass = 74/2 = 37
No: of equivalents = 1.35/37 = 0.036
Normality = 0.036/875 * 1000 = 0.041N

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