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If in an 0.050 M aqueous solution of hydroxlamine, HONH2 at 20 degrees Celcius, [OH-] = 2.

If in an 0.050 M aqueous solution of hydroxlamine, HONH2 at 20 degrees Celcius, [OH-] = 2.3 x 10 ^-5M, What is Kb for HONH2 at 20 degrees Celcius, and what are the equilibrium concentrations  of HONH2, HONH3, and OH- in a 0.0010 M HONH2 solution.
HONH2 + H2O =HONH3 + OH

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