Calculate the amount of heat that must be absorbed by 10.0 g of ice at -20.0 degrees C to convert it to liquid water at 60.0 degree C.

Specific heat (ice) = 2.1 j/g degree C

Specific heat (water) delta H (fus)= 6.0 kJ/mol

Specific heat (ice) = 2.1 j/g degree C

Specific heat (water) delta H (fus)= 6.0 kJ/mol

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