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Hydrofluoric acid (HF) has a Ka value of 7.2 x 10 ^ - 4. Part a: 0.250 mol of F - ions (in the form of NaF) are added to 1.0 Liters of 0.1 mol L-1

Hydrofluoric acid (HF) has a Ka value of 7.2 x 10 ^ - 4.
Part a: 0.250 mol of F - ions (in the form of NaF) are added to 1.0 Liters of 0.1 mol L-1 aqueous HF.  Calculate the resulting PH?
Part b:  To the solution produced in (part a) is added 10.0 ml of 5.0 mol L-1 NaOH. Calculate the resulting PH?
I was able to set up and solve part a, I got the PH as 3.54.   I am not sure how to set up and solve part b.

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