what is the theoretical mole ratio- NaCl to NaHCO3

How do you determine the percentage error of an experimental mole ratioIt would be easier for us to help you if we had the entire problem instead of just parts of it. However, from the standpoint of Na, the mole ratio of NaCl to NaHCO3 as a stand alone question, is 1:1.

Percent error is:

%error = [difference/correct value]x100

where "difference" is

correct value-experimental value.

okay..i believe this is the balanced equation--

NaHCO3 + HCl----->NaCl+CO2+H2O

now,using the balanced equation, calculate the mass of NaCl you would expect to get when 2.50 grams of NaHCO3 react with HCL

mass or reactant, NaHCO3........2

moles of NaHCO3 reacted......... .024

mass of product, NaCl........1.34

moles of NaCl produced........ .023

experimetal mole ratio- NaCl to NaHCO3...... ?

theoretical mole ratio - NaCl to NaHCO3..... ?

percentage error of experimetal mole ratio....... ?

i don't know how to find the mole ratios of these three and i really need some help on answering them with the information that was given above. yup that is it man

How do you determine the percentage error of an experimental mole ratioIt would be easier for us to help you if we had the entire problem instead of just parts of it. However, from the standpoint of Na, the mole ratio of NaCl to NaHCO3 as a stand alone question, is 1:1.

Percent error is:

%error = [difference/correct value]x100

where "difference" is

correct value-experimental value.

okay..i believe this is the balanced equation--

NaHCO3 + HCl----->NaCl+CO2+H2O

now,using the balanced equation, calculate the mass of NaCl you would expect to get when 2.50 grams of NaHCO3 react with HCL

mass or reactant, NaHCO3........2

moles of NaHCO3 reacted......... .024

mass of product, NaCl........1.34

moles of NaCl produced........ .023

experimetal mole ratio- NaCl to NaHCO3...... ?

theoretical mole ratio - NaCl to NaHCO3..... ?

percentage error of experimetal mole ratio....... ?

i don't know how to find the mole ratios of these three and i really need some help on answering them with the information that was given above. yup that is it man

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