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BrO3- + 5Br- + 6H+ <--> 3Br2 + 3H2O If 25.0 ml of 0.200-molar BrO3- is mixed with 30.0 ml of 0.

BrO3- + 5Br- + 6H+ <--> 3Br2 + 3H2O
If 25.0 ml of 0.200-molar BrO3- is mixed with 30.0 ml of 0.45-molar Br- solution that contains a large excess of H+, what is the amount of Br2 formed, according to the above equation?
The answer is 0.00810 moles but I don't know how to approach this!
I have the final exam tomorrow. Pleas help me!
Thanks!

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