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Kp = 1.78 at 250C for the decomposition reaction, PCl5(g) l PCl3(g) + Cl2(g). Calculate the percentage of reactant that remains if 10.

Kp = 1.78 at 250ºC for the decomposition reaction, PCl5(g) l PCl3(g) + Cl2(g). Calculate the percentage of reactant that remains if 10.0 moles of starting material are placed in a closed vessel at this temperature and 2.00 atm pressure. Also, determine the value of Kc for this reaction at 250ºC.

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Kp = 1.78 Initial pressure of Pcl5 = 2 atm PCl5(g) <--> PCl3(g) + Cl2(g) Let the pressure of Pcl3 and cl2 at... View the full answer

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