A sample of Oxygen has occupies 1.00x10^6mL at 575mm Hg is subjected to a pressure of 1.25atm. What will the final volume of the sample be if the temperature is held constant

v2=(p1)(p2)/p2

I'll have to convert 1.25atm to mm first

1.25atm*760mm/1.0atm = 950. mm

V2=(575mm)(1.00x10^6mL)/950.mm

=6.05x10^5

Can you check my math and method?

v2=(p1)(p2)/p2

I'll have to convert 1.25atm to mm first

1.25atm*760mm/1.0atm = 950. mm

V2=(575mm)(1.00x10^6mL)/950.mm

=6.05x10^5

Can you check my math and method?

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