View the step-by-step solution to: 1. 1.00 mL of a 3.60 10-4 M solution of oleic acid is

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1. 1.00 mL of a 3.60  10–4 M solution of oleic acid is diluted with 9.00 mL of petroleum ether, forming solution A. Then 2.00 mL of solution A is diluted with 8.00 mL of petroleum ether, forming solution B. How many grams of oleic acid are 5.00 mL of solution B? (Molar mass for oleic acid = 282 g/mol)
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