4Al(s) + 3O2(g) --> 2Al2O3(s)
A mixture of 82.49 g of aluminum (MM = 26.98 g/mol) and 117.65 g of oxygen (MM = 32.00 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete.
This question was asked on Nov 05, 2010.
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