4Al(s) + 3O2(g) --> 2Al2O3(s)
A mixture of 82.49 g of aluminum (MM = 26.98 g/mol) and 117.65 g of oxygen (MM = 32.00 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete.
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