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CHEM 111 Chapter 6 Homework 1) Are the following processes exothermic or endothermic ?(3 pts) a. When solid KBr is dissolved in water, the solution

My assignment is attached in PDF format. Please do not assign this to the one who did my lab assignment before on limiting reactants because I scored very low. In this assignment, kindly show step-by-step how you arrive at the answers. My professor deducts points when it only gives the answer with no step-by-step analysis of the answer.
CHEM 111 Chapter 6 Homework 1) Are the following processes exothermic or endothermic ?(3 pts) a. When solid KBr is dissolved in water, the solution gets colder b. Natural gas (CH 4 ) is burned in a furnace c. When concentrated H 2 SO 4 is added to water, the solution gets very hot 2) Which type of energy, kinetic or potential? a.A brick sitting on a high shelf b. A steam engine heading toward Denver c. A tank of diesel fuel 2) For the reaction (6 pts) S (s) + O 2 (g) -----> SO 2 (g) H = -296 KJ/mol a.How much heat is evolved when 275 g of sulfur is burned in excess oxygen ? b. How much heat is evolved when 25 mol of sulfur is burned in excess oxygen ? 3) The specific heat capacity of aluminum is 0.900 J/gC (4 pts) a. Calculate the energy needed to raise the temperature of a 850 g block of Al from 22.8 C to 94.6 C 4) It takes 78.2 J to raise the temperature of 45.6 g of lead by 13.3 C. Calculate the specific heat capacity ( 3 pt)
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5) If 5 g of CaCl 2 is dissolved in water how much energy is liberated ? H soln for CaCl 2 = -81.3 KJ/mol ( 3 pts) 6) Given the following data: (5 pts) S (s) + 3/2 O 2 (g) -----> SO 3 (g) H = -395.2 KJ 2 SO 2 (g) + O 2 (g) -----> 2 SO 3 (g) H = -198.2 KJ Calculate the H for the reaction S (s) + O 2 (g) -----> SO 2 (g) 7) Calculate the enthalpy change for this reaction P 4 O 6 + 2 O 2 --- P 4 O 10 Given the following data: P 4 (s) + 3 O 2 (g) --- P 4 O 6 (s) H = -1640.1 KJ P 4 (s) + 5 O 2 (g) --- P 4 O 10 (s) H = -2940.1 KJ
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chemistry . .. ,.doc

8) Given the following data: (8 pts)
H2 (g) + ½ O2 (g) -----> H2O (l) H = -285.8 KJ∆
N2O5 (g) + H2O (l) -----> 2 HNO3 (l) H = -76.6 KJ∆
½ N2 (g) + 3/2 O2 (g) + ½ H2 (g) -----> HNO3...

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